I'm using CENTCIR to find the location of the pin within my contour. I can find the center of the circle, but how can I evaluate the distance to the end of the pin?
Attached is a print snippet. How can I evaluate the 2.7753 and 1.5175 dimensions?
Hello
Evaluate the distance from the upper planen to centerpoint and add half the center circle diameter.
Evaluate the distance from the rigt plane to P2.
Hello Evaluate the distance from the upper planen to centerpoint and add half the center circle diameter. Evaluate the distance from the rigt plane to P2.
Hope this helps.
I was thinking there might be a command for this such as 3McdCirCir2, except one element would be an axis. There is a command MCDCIAX. but this is to the center of the circle.
I was thinking there might be a command for this such as 3McdCirCir2, except one element would be an axis. There is a command MCDCIAX. but this is to the center of the circle.
Also, The P2 tangency point and the maximum point on the circle are dfferent.
Hello.
What i can see on the drawing the 1.5175 distance is to the tangency point.
I did a test om a Cad model. You must insert your own values and element names.
Hello. What i can see on the drawing the 1.5175 distance is to the tangency point. I did a test om a Cad model. You must insert your own values and element names.
!Calculate the distance to the centerpoint DIPNTAXI (NAM=DIS(1), CSY=CSY(1), EL1=CENT, EL2=AXI(1), CPY=DEF$DIS1)
!Calculate the distance to the tangentpoint DIPNTAXI (NAM=DIS(2), CSY=CSY(1), EL1=PNT2, EL2=AXI(2), CPY=DEF$DIS1)
!Add the radius off the centering ball XY=DIS(1).$A+50
!Run DFNELE just one time DFNELE (NAM=DIS(3), TYP=POI, CSY=CSY(1))
!Add the calculated realvalue to the element PUTVAL (OBJ=DIS(3), DSC=X, TYP=ELE, VAL=XY)
!Evaluate AddEva (NAM=DIS(3), EDT=N)
Hope this helps
That does help to find the distance to the point of tangency. Thank you.
The distance from the edge to the POT is 1.5136. The distance to the end of the pin is 1.5175. I'm trying to figure out the best way to add the pin radius (.175) to the center distance then evaluate.
First you calculate the distance to the center of the centering circle.
Make sure that the distance in Z betveen the axis and profil i close to zero, otherwise you have to prjekt the points (PRJPTS)
First you calculate the distance to the center of the centering circle. Make sure that the distance in Z betveen the axis and profil i close to zero, otherwise you have to prjekt the points (PRJPTS)
Now THAT is what I was looking for. Actually, the previous example will also be very useful. I have several variations of that profile with different pin diameters that I need to write programs for. Thank you for taking the time with a detailed solution !
