SETITR for cones

Hi Bruno, Your inputs are a bit mixed up. You have inputted the base dia, which is not relevant. You must input the coordinates of the base point in X,Y,Z & then the angle. Fix X,Y,Z,A & it should work.

If you generate the cone, you can find the base point coordinates in the Nominal element.

Here's an example to play about with :

GENCON (NAM=Cone, XCO=0, YCO=0, ZCO=0, DIA=10, NPT=12, DIR=-X, INO=O, LEN=10, NPL=3, ANG=90, DEL=Y, RTP=0, OFS=1)
SETITR (NAM=Cone, TYP=CON, X =-5, Y =0, Z =0, VAL=90, DIR=-X, INO=O, FIX=Y, FIY=N, FIZ=N, FID=N, FIA=Y, LCK=Y)
EXCHNG (NAM=Cone, MOD=MOV)
MECON (NAM=Cone, MOD=(NOM,NOE), INO=O)
EDTAPT (NAM=Cone)

Hello Timothy I'm really grateful for your guidance, only I want to clarify one point to really understand all

When you said "base point" are you talking about vertex of the cone or im wrong?

When I see the X,Y,Z of the nominal calculated cone -5,0,0 it matches with the NPTs where the vertex is --> Is the vertex point the data (X,Y,Z) I will get after generate & calculate a nominal cone right?

and do you know if is possible to use the nominal cone in the field "Element to use to fix the constraints"  if i write the nominal element here will be enough to constraint the characteristics of the nominal element?

Thanks a lot in advance

BG

If you generate a cone, Quindos calculates the vertex (tip) location. You can use this value to fix the iteration in X,Y,Z.

I used this command & it works :

SETITR (NAM=Cone, TYP=CON, INO=O, FIX=Y, FIY=N, FIZ=N, FID=N, FIA=Y, ELE=Cone.NOM, LCK=Y)

Thanks a lot Timothy ;)